What is the tangent of f(x)=3x^2,\at x=2 ?

The tangent of f(x)=3x^2,\at x=2 is y=12x-12

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tangent of f(x)=3x^2,\at x=2

tangent of

f (x) = 3 x^{2}, at x = 2

y = 12 x - 12

Solution steps

Find the tangent point:

(2, 12)

Find the slope of

f (x) = 3 x^{2} : \frac{df ( x )}{d x} = 6 x

Compute the slope of

f (x) = 3 x^{2}

x = 2 : m = 12

Find the line with slope m=

12

and passing through

(2, 12) : y = 12 x - 12

y = 12 x - 12

f (x) = 4 e^{- 2 x} - 9 x + 1 (0.5)

4 x - 1

f (x) = \frac{1}{3 x ^{2}}

y - 3 = 5 (x - 2)

f (x) = x + \frac{1}{x}

What is the tangent of f(x)=3x^2,\at x=2 ?
The tangent of f(x)=3x^2,\at x=2 is y=12x-12