What is the first derivative of 4x-1 ?

The first derivative of 4x-1 is 4

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derivative of 4x-1

derivative of

4 x - 1

4

Solution steps

\frac{d}{d x} (4 x - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x) - \frac{d}{d x} (1)

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= 4 - 0

Simplify

= 4

f (x) = \frac{1}{3 x ^{2}}

y - 3 = 5 (x - 2)

f (x) = x + \frac{1}{x}

(- \frac{17}{8}, - \frac{19}{6}), (\frac{25}{6}, \frac{3}{2})

(0, - 10)