What is the first derivative of 2x^2 ?

The first derivative of 2x^2 is 4x

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derivative of 2x^2

derivative of

2 x^{2}

4 x

Solution steps

\frac{d}{d x} (2 x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 2 x^{2 - 1}

Simplify

= 4 x

y = 3 x + 2

y = 2 x + 3

(- 4.5) (0.8)

f (x) = sin^{3} (x)

f (x) = \frac{3 x ^{2} + 6 x + 4}{x}