What is the first derivative of y=3x+2 ?

The first derivative of y=3x+2 is 3

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derivative of y=3x+2

derivative of

y = 3 x + 2

3

Solution steps

\frac{d}{d x} (3 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (2) = 0

= 3 + 0

Simplify

= 3

y = 2 x + 3

(- 4.5) (0.8)

f (x) = sin^{3} (x)

f (x) = \frac{3 x ^{2} + 6 x + 4}{x}

(- 4, \frac{7 π}{6})