derivative f(x)=7x^4-8x^5+1

الحلّ

derivative of

f (x) = 7 x^{4} - 8 x^{5} + 1

- 40 x^{4} + 28 x^{3}

خطوات الحلّ

\frac{d}{d x} (7 x^{4} - 8 x^{5} + 1)

(f \pm g)^{'} = f^{'} \pm g^{'}

:استعمل قانون الجمع

= \frac{d}{d x} (7 x^{4}) - \frac{d}{d x} (8 x^{5}) + \frac{d}{d x} (1)

\frac{d}{d x} (7 x^{4}) = 28 x^{3}

\frac{d}{d x} (8 x^{5}) = 40 x^{4}

\frac{d}{d x} (1) = 0

= 28 x^{3} - 40 x^{4} + 0

بسّط

= - 40 x^{4} + 28 x^{3}

2 x - 3 y = 5, at x = \frac{7}{2}

4 x + 3 y = 12

y = ln (\frac{x + 1}{x - 1})

(- 2, 6), (3, - 2)

f (x) = x^{2}, at x = 1