What is 5-3\times (2\times (4-1)-3(-(-5))-8\div 4-2) ?

The solution to 5-3\times (2\times (4-1)-3(-(-5))-8\div 4-2) is 44

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5-3\times (2\times (4-1)-3(-(-5))-8\div 4-2)

5 - 3 \times (2 \times (4 - 1) - 3 (- (- 5)) - 8 \div 4 - 2)

44

Solution steps

5 - 3 \times (2 \times (4 - 1) - 3 (- (- 5)) - 8 \div 4 - 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(2 \times (4 - 1) - 3 (- (- 5)) - 8 \div 4 - 2) : - 13

2 \times (4 - 1) - 3 (- (- 5)) - 8 \div 4 - 2

Calculate within parentheses

(4 - 1) : 3

4 - 1

4 - 1 = 3

= 3

= 2 \times 3 - 3 (- (- 5)) - 8 \div 4 - 2

Calculate within parentheses

(- (- 5)) : 5

- (- 5)

- (- 5) = 5

= 5

= 2 \times 3 - 3 \cdot 5 - 8 \div 4 - 2

Multiply and divide (left to right)

2 \times 3 : 6

2 \times 3

2 \times 3 = 6

= 6

= 6 - 3 \cdot 5 - 8 \div 4 - 2

Multiply and divide (left to right)

3 \cdot 5 : 15

3 \cdot 5

3 \cdot 5 = 15

= 15

= 6 - 15 - 8 \div 4 - 2

Multiply and divide (left to right)

8 \div 4 : 2

8 \div 4

8 \div 4 = 2

= 2

= 6 - 15 - 2 - 2

Add and subtract (left to right)

6 - 15 - 2 - 2 : - 13

6 - 15 - 2 - 2

6 - 15 = - 9

= - 9 - 2 - 2

- 9 - 2 = - 11

= - 11 - 2

- 11 - 2 = - 13

= - 13

= - 13

= 5 - 3 \times (- 13)

Multiply and divide (left to right)

3 \times (- 13) : - 39

3 \times (- 13)

Apply rule

a \times (- b) = - a \times b

3 \times (- 13) = - 3 \times 13 = - 39

= - 39

= 5 - (- 39)

Add and subtract (left to right)

5 - (- 39) : 44

5 - (- 39)

Apply rule

- (- a) = + a

- (- 39) = + 39

= 5 + 39

5 + 39 = 44

= 44

= 44

7 + (- 105) + 94

20 (- 4) \div 10 - 6 \div (5 - 7)

2 + 9 (12 \div 2 \times 6)

(- 18 - 15) \div 33 - 30 \div [(11 - 13) - (16 - 15 \div 5)]

- 1 - 3 + 5

What is 5-3\times (2\times (4-1)-3(-(-5))-8\div 4-2) ?
The solution to 5-3\times (2\times (4-1)-3(-(-5))-8\div 4-2) is 44