What is -(-1)^4-(-1)^3+(-1^2)+(-1)-1 ?

The solution to -(-1)^4-(-1)^3+(-1^2)+(-1)-1 is -3

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-(-1)^4-(-1)^3+(-1^2)+(-1)-1

- (- 1)^{4} - (- 1)^{3} + (- 1^{2}) + (- 1) - 1

- 3

Solution steps

- (- 1)^{4} - (- 1)^{3} + (- 1^{2}) + (- 1) - 1

Follow the PEMDAS order of operations

Calculate within parentheses

(- 1^{2}) : - 1

- 1^{2}

- 1^{2} = - 1

= - 1

= - (- 1)^{4} - (- 1)^{3} - 1 + (- 1) - 1

Calculate exponents

(- 1)^{4} : 1

(- 1)^{4}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 1)^{4} = 1^{4} = 1

= 1

= - 1 - (- 1)^{3} - 1 + (- 1) - 1

Calculate exponents

(- 1)^{3} : - 1

(- 1)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 1)^{3} = - 1^{3} = - 1

= - 1

= - 1 - (- 1) - 1 + (- 1) - 1

Add and subtract (left to right)

- 1 - (- 1) - 1 + (- 1) - 1 : - 3

- 1 - (- 1) - 1 + (- 1) - 1

Apply rule

- (- a) = + a

- (- 1) = + 1

= - 1 + 1 - 1 + (- 1) - 1

- 1 + 1 = 0

= 0 - 1 + (- 1) - 1

0 - 1 = - 1

= - 1 + (- 1) - 1

Apply rule

+ (- a) = - a

+ (- 1) = - 1

= - 1 - 1 - 1

- 1 - 1 = - 2

= - 2 - 1

- 2 - 1 = - 3

= - 3

= - 3

\frac{5 ^{2} - 16}{5 - 4}

- 8 \div 4 \cdot 18 - (- 43) + 7 \cdot 6

(- 2)^{3} + \frac{48}{- 2}

- \frac{11}{8} (2)^{3}

3 - \frac{5}{8} + \frac{1}{3}

What is -(-1)^4-(-1)^3+(-1^2)+(-1)-1 ?
The solution to -(-1)^4-(-1)^3+(-1^2)+(-1)-1 is -3