What is 7+5× 3-(1× 5+16)\div 8+(4× 2) ?

The solution to 7+5× 3-(1× 5+16)\div 8+(4× 2) is 27 3/8

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Popular Pre Algebra >

7+5× 3-(1× 5+16)\div 8+(4× 2)

Solution

7 + 5 \times 3 - (1 \times 5 + 16) \div 8 + (4 \times 2)

Solution

27 \frac{3}{8}

Decimal

27.375

Solution steps

7 + 5 \times 3 - (1 \times 5 + 16) \div 8 + (4 \times 2)

Follow the PEMDAS order of operations

Calculate within parentheses

(1 \times 5 + 16) : 21

1 \times 5 + 16

Multiply and divide (left to right)

1 \times 5 : 5

1 \times 5

1 \times 5 = 5

= 5

= 5 + 16

Add and subtract (left to right)

5 + 16 : 21

5 + 16

5 + 16 = 21

= 21

= 21

= 7 + 5 \times 3 - 21 \div 8 + (4 \times 2)

Calculate within parentheses

(4 \times 2) : 8

4 \times 2

4 \times 2 = 8

= 8

= 7 + 5 \times 3 - 21 \div 8 + 8

Multiply and divide (left to right)

5 \times 3 : 15

5 \times 3

5 \times 3 = 15

= 15

= 7 + 15 - 21 \div 8 + 8

Multiply and divide (left to right)

21 \div 8 : \frac{21}{8}

21 \div 8

21 \div 8 = \frac{21}{8}

= \frac{21}{8}

= 7 + 15 - \frac{21}{8} + 8

Add and subtract (left to right)

7 + 15 - \frac{21}{8} + 8 : \frac{219}{8}

7 + 15 - \frac{21}{8} + 8

7 + 15 = 22

= 22 - \frac{21}{8} + 8

22 - \frac{21}{8} = \frac{155}{8}

22 - \frac{21}{8}

Convert element to fraction:

22 = \frac{22 \cdot 8}{8}

= \frac{22 \cdot 8}{8} - \frac{21}{8}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{22 \cdot 8 - 21}{8}

22 \cdot 8 - 21 = 155

22 \cdot 8 - 21

Multiply the numbers:

22 \cdot 8 = 176

= 176 - 21

Subtract the numbers:

176 - 21 = 155

= 155

= \frac{155}{8}

= \frac{155}{8} + 8

\frac{155}{8} + 8 = \frac{219}{8}

\frac{155}{8} + 8

Convert element to fraction:

8 = \frac{8 \cdot 8}{8}

= \frac{8 \cdot 8}{8} + \frac{155}{8}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{8 \cdot 8 + 155}{8}

8 \cdot 8 + 155 = 219

8 \cdot 8 + 155

Multiply the numbers:

8 \cdot 8 = 64

= 64 + 155

Add the numbers:

64 + 155 = 219

= 219

= \frac{219}{8}

= \frac{219}{8}

= \frac{219}{8}

Convert improper fractions to mixed numbers:

\frac{219}{8} = 27 \frac{3}{8}

\frac{219}{8} = 27

Remainder

3

\frac{219}{8}

Write the problem in long division format

8 \overline{∣ 219}

Divide

21

8

to get

2

Divide

21

8

to get

2

2 8 \overline{∣ 219}

Multiply the quotient digit

(2)

by the divisor

8

2 8 \overline{∣ 219} \underline{16}

Subtract

16

from

21

2 8 \overline{∣ 219} \underline{16} 5

Bring down the next number of the dividend

2 8 \overline{∣ 219} \underline{16} 59

2 8 \overline{∣ 219} \underline{16} 59

Divide

59

8

to get

7

Divide

59

8

to get

7

27 8 \overline{∣ 219} \underline{16} 59

Multiply the quotient digit

(7)

by the divisor

8

27 8 \overline{∣ 219} \underline{16} 59 \underline{56}

Subtract

56

from

59

27 8 \overline{∣ 219} \underline{16} 59 \underline{56} 3

27 8 \overline{∣ 219} \underline{16} 59 \underline{56} 3

The solution for Long Division of

\frac{219}{8}

27

with remainder of

3

27 Remainder 3

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{219}{8} = 27 \frac{3}{8}

= 27 \frac{3}{8}

= 27 \frac{3}{8}

Popular Examples

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Frequently Asked Questions (FAQ)

What is 7+5× 3-(1× 5+16)\div 8+(4× 2) ?
The solution to 7+5× 3-(1× 5+16)\div 8+(4× 2) is 27 3/8

7+5× 3-(1× 5+16)\div 8+(4× 2)

Solution

Solution

Popular Examples

Frequently Asked Questions (FAQ)

What is 7+5× 3-(1× 5+16)\div 8+(4× 2) ?

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