What is -(-2)^2+2(-2) ?

The solution to -(-2)^2+2(-2) is -8

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-(-2)^2+2(-2)

- (- 2)^{2} + 2 (- 2)

- 8

Solution steps

- (- 2)^{2} + 2 (- 2)

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

(- 2)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 2)^{2} = 2^{2} = 4

= 4

= - 4 + 2 (- 2)

Multiply and divide (left to right)

2 (- 2) : - 4

2 (- 2)

Apply rule

a \cdot (- b) = - a \cdot b

2 (- 2) = - 2 \cdot 2 = - 4

= - 4

= - 4 - 4

Add and subtract (left to right)

- 4 - 4 : - 8

- 4 - 4

- 4 - 4 = - 8

= - 8

= - 8

\frac{3 \cdot 2 ^{9} + 6 \cdot 2 ^{5}}{1 2 ^{3}}

7 - (7 + 2) \div 3

17 - 3 \times (8 - 4) + 54 \div 2

10 \cdot [- 2 + 4 \cdot (3 - 5 \cdot 2)]

(1 0^{2} \div (6 + 8 - 9)^{2}) \times 4