What is 10*[-2+4*(3-5*2)] ?

The solution to 10*[-2+4*(3-5*2)] is -300

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10[-2+4(3-5*2)]

10 \cdot [- 2 + 4 \cdot (3 - 5 \cdot 2)]

- 300

Solution steps

10 [- 2 + 4 (3 - 5 \cdot 2)]

Follow the PEMDAS order of operations

Calculate within parentheses

[- 2 + 4 \cdot (3 - 5 \cdot 2)] : - 30

- 2 + 4 (3 - 5 \cdot 2)

Calculate within parentheses

(3 - 5 \cdot 2) : - 7

3 - 5 \cdot 2

Multiply and divide (left to right)

5 \cdot 2 : 10

5 \cdot 2

5 \cdot 2 = 10

= 10

= 3 - 10

Add and subtract (left to right)

3 - 10 : - 7

3 - 10

3 - 10 = - 7

= - 7

= - 7

= - 2 + 4 (- 7)

Multiply and divide (left to right)

4 (- 7) : - 28

4 (- 7)

Apply rule

a \cdot (- b) = - a \cdot b

4 (- 7) = - 4 \cdot 7 = - 28

= - 28

= - 2 - 28

Add and subtract (left to right)

- 2 - 28 : - 30

- 2 - 28

- 2 - 28 = - 30

= - 30

= - 30

= 10 (- 30)

Multiply and divide (left to right)

10 (- 30) : - 300

10 (- 30)

Apply rule

a \cdot (- b) = - a \cdot b

10 (- 30) = - 10 \cdot 30 = - 300

= - 300

= - 300

(1 0^{2} \div (6 + 8 - 9)^{2}) \times 4

+ (- 7 - (8 - 9 - 11 - 9 + 20 - 7) - 7 + 8 - 1) - 7

2^{4} + 18 \div 2

5 \times 4 \div 10 + 40 - 7

8 \frac{1}{5} + (3 \frac{2}{5} + 5 \frac{4}{5})