What is 90-5-10-10-(118\div 150)30 ?

The solution to 90-5-10-10-(118\div 150)30 is 41 2/5

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Popular Pre Algebra >

90-5-10-10-(118\div 150)30

Solution

90 - 5 - 10 - 10 - (118 \div 150) 30

Solution

41 \frac{2}{5}

Decimal

41.4

Solution steps

90 - 5 - 10 - 10 - (118 \div 150) \cdot 30

Follow the PEMDAS order of operations

Calculate within parentheses

(118 \div 150) : \frac{118}{150}

118 \div 150

118 \div 150 = \frac{118}{150}

= \frac{118}{150}

= 90 - 5 - 10 - 10 - \frac{118}{150} \cdot 30

Multiply and divide (left to right)

\frac{118}{150} \cdot 30 : \frac{118}{5}

\frac{118}{150} \cdot 30

Cancel

\frac{118}{150} : \frac{59}{75}

\frac{118}{150}

Factor the number:

118 = 2 \cdot 59

= \frac{2 \cdot 59}{150}

Factor the number:

150 = 2 \cdot 75

= \frac{2 \cdot 59}{2 \cdot 75}

Cancel the common factor:

2

= \frac{59}{75}

= \frac{59}{75} \cdot 30

\frac{59}{75} \cdot 30 = \frac{118}{5}

\frac{59}{75} \cdot 30

Convert element to fraction:

30 = \frac{30}{1}

= \frac{59}{75} \cdot \frac{30}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{59 \cdot 30}{75 \cdot 1}

Cancel

\frac{59 \cdot 30}{75 \cdot 1} : \frac{118}{5}

\frac{59 \cdot 30}{75 \cdot 1}

Multiply the numbers:

75 \cdot 1 = 75

= \frac{59 \cdot 30}{75}

Factor the number:

30 = 15 \cdot 2

= \frac{59 \cdot 15 \cdot 2}{75}

Factor the number:

75 = 15 \cdot 5

= \frac{59 \cdot 15 \cdot 2}{15 \cdot 5}

Cancel the common factor:

15

= \frac{59 \cdot 2}{5}

Multiply the numbers:

59 \cdot 2 = 118

= \frac{118}{5}

= \frac{118}{5}

= \frac{118}{5}

= 90 - 5 - 10 - 10 - \frac{118}{5}

Add and subtract (left to right)

90 - 5 - 10 - 10 - \frac{118}{5} : \frac{207}{5}

90 - 5 - 10 - 10 - \frac{118}{5}

90 - 5 = 85

= 85 - 10 - 10 - \frac{118}{5}

85 - 10 = 75

= 75 - 10 - \frac{118}{5}

75 - 10 = 65

= 65 - \frac{118}{5}

65 - \frac{118}{5} = \frac{207}{5}

65 - \frac{118}{5}

Convert element to fraction:

65 = \frac{65 \cdot 5}{5}

= \frac{65 \cdot 5}{5} - \frac{118}{5}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{65 \cdot 5 - 118}{5}

65 \cdot 5 - 118 = 207

65 \cdot 5 - 118

Multiply the numbers:

65 \cdot 5 = 325

= 325 - 118

Subtract the numbers:

325 - 118 = 207

= 207

= \frac{207}{5}

= \frac{207}{5}

= \frac{207}{5}

Convert improper fractions to mixed numbers:

\frac{207}{5} = 41 \frac{2}{5}

\frac{207}{5} = 41

Remainder

2

\frac{207}{5}

Write the problem in long division format

5 \overline{∣ 207}

Divide

20

5

to get

4

Divide

20

5

to get

4

4 5 \overline{∣ 207}

Multiply the quotient digit

(4)

by the divisor

5

4 5 \overline{∣ 207} \underline{20}

Subtract

20

from

20

4 5 \overline{∣ 207} \underline{20} 0

Bring down the next number of the dividend

4 5 \overline{∣ 207} \underline{20} 07

4 5 \overline{∣ 207} \underline{20} 07

Divide

7

5

to get

1

Divide

7

5

to get

1

41 5 \overline{∣ 207} \underline{20} 07

Multiply the quotient digit

(1)

by the divisor

5

41 5 \overline{∣ 207} \underline{20} 07 \underline{5}

Subtract

5

from

7

41 5 \overline{∣ 207} \underline{20} 07 \underline{5} 2

41 5 \overline{∣ 207} \underline{20} 07 \underline{5} 2

The solution for Long Division of

\frac{207}{5}

41

with remainder of

2

41 Remainder 2

Convert to mixed number: Quotient

\frac{Remainder}{Divisor}

\frac{207}{5} = 41 \frac{2}{5}

= 41 \frac{2}{5}

= 41 \frac{2}{5}

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Frequently Asked Questions (FAQ)

What is 90-5-10-10-(118\div 150)30 ?
The solution to 90-5-10-10-(118\div 150)30 is 41 2/5

90-5-10-10-(118\div 150)30

Solution

Solution

Popular Examples

Frequently Asked Questions (FAQ)

What is 90-5-10-10-(118\div 150)30 ?

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