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受欢迎的初等代数 >

(2+1 1/2)-2 1/2

解答

(2 + 1 \frac{1}{2}) - 2 \frac{1}{2}

解答

1

求解步骤

(2 + 1 \frac{1}{2}) - 2 \frac{1}{2}

将带分数转换为假分式:

2 \frac{1}{2} = \frac{5}{2}

2 \frac{1}{2}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

2 \frac{1}{2} = \frac{2 \cdot 2 + 1}{2}

= \frac{5}{2}

= (2 + 1 \frac{1}{2}) - \frac{5}{2}

将带分数转换为假分式:

1 \frac{1}{2} = \frac{3}{2}

1 \frac{1}{2}

将带分数转换为假分式:

a \frac{b}{c} = \frac{a \cdot c + b}{c}

1 \frac{1}{2} = \frac{1 \cdot 2 + 1}{2}

= \frac{3}{2}

= (2 + \frac{3}{2}) - \frac{5}{2}

遵循 PEMDAS 运算顺序

计算括号内的值

(2 + \frac{3}{2}) : \frac{7}{2}

2 + \frac{3}{2}

2 + \frac{3}{2} = \frac{7}{2}

2 + \frac{3}{2}

将项转换为分式:

2 = \frac{2 \cdot 2}{2}

= \frac{2 \cdot 2}{2} + \frac{3}{2}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{2 \cdot 2 + 3}{2}

2 \cdot 2 + 3 = 7

2 \cdot 2 + 3

数字相乘:

2 \cdot 2 = 4

= 4 + 3

数字相加:

4 + 3 = 7

= 7

= \frac{7}{2}

= \frac{7}{2}

= \frac{7}{2} - \frac{5}{2}

加减（左右）

\frac{7}{2} - \frac{5}{2} : 1

\frac{7}{2} - \frac{5}{2}

\frac{7}{2} - \frac{5}{2} = 1

\frac{7}{2} - \frac{5}{2}

使用法则

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{7 - 5}{2}

数字相减:

7 - 5 = 2

= \frac{2}{2}

使用法则

\frac{a}{a} = 1

= 1

= 1

= 1

流行的例子

2^7+2^6+2^5+2^4+2^3+2^2

(3/9 \div 3/1) 4/1