What is 10-(5-2)+10\times 2-8 ?

The solution to 10-(5-2)+10\times 2-8 is 19

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10-(5-2)+10\times 2-8

10 - (5 - 2) + 10 \cdot 2 - 8

19

Solution steps

10 - (5 - 2) + 10 \cdot 2 - 8

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - 2) : 3

5 - 2

5 - 2 = 3

= 3

= 10 - 3 + 10 \cdot 2 - 8

Multiply and divide (left to right)

10 \cdot 2 : 20

10 \cdot 2

10 \cdot 2 = 20

= 20

= 10 - 3 + 20 - 8

Add and subtract (left to right)

10 - 3 + 20 - 8 : 19

10 - 3 + 20 - 8

10 - 3 = 7

= 7 + 20 - 8

7 + 20 = 27

= 27 - 8

27 - 8 = 19

= 19

= 19

(3^{2}) (3 + 4^{2} - 2^{3} + 3) \div (2 + 4)

\frac{8}{3} - 4 + 4

4 \times 14 \div (7) + 9 \times (3) - 2 \div (- 2)

5 - \frac{12}{7} + \frac{9}{7}

(1 - \frac{3}{2}) \div (1 - \frac{4}{3})