What is (-6-3)^2+(-11+4) ?

The solution to (-6-3)^2+(-11+4) is 74

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(-6-3)^2+(-11+4)

(- 6 - 3)^{2} + (- 11 + 4)

74

Solution steps

(- 6 - 3)^{2} + (- 11 + 4)

Follow the PEMDAS order of operations

Calculate within parentheses

(- 6 - 3) : - 9

- 6 - 3

- 6 - 3 = - 9

= - 9

= (- 9)^{2} + (- 11 + 4)

Calculate within parentheses

(- 11 + 4) : - 7

- 11 + 4

- 11 + 4 = - 7

= - 7

= (- 9)^{2} - 7

Calculate exponents

(- 9)^{2} : 81

(- 9)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 9)^{2} = 9^{2} = 81

= 81

= 81 - 7

Add and subtract (left to right)

81 - 7 : 74

81 - 7

81 - 7 = 74

= 74

= 74

2 4^{2} - 1 0^{2}

1 - 9 + 4

36 (2)^{2} - 72 (2) + 33

24 \div (- 8) + 6 - (- 5)

\frac{- 3}{5} \cdot (5 - \frac{2}{3})