What is (-3)/5*(5-2/3) ?

The solution to (-3)/5*(5-2/3) is -13/5

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(-3)/5*(5-2/3)

\frac{- 3}{5} \cdot (5 - \frac{2}{3})

- \frac{13}{5}

Solution steps

\frac{- 3}{5} (5 - \frac{2}{3})

Apply the fraction rule

\frac{- a}{b} = - \frac{a}{b}

- \frac{3}{5}

= (- \frac{3}{5}) (5 - \frac{2}{3})

Follow the PEMDAS order of operations

Calculate within parentheses

(5 - \frac{2}{3}) : \frac{13}{3}

5 - \frac{2}{3}

5 - \frac{2}{3} = \frac{13}{3}

5 - \frac{2}{3}

Convert element to fraction:

5 = \frac{5 \cdot 3}{3}

= \frac{5 \cdot 3}{3} - \frac{2}{3}

Since the denominators are equal, combine the fractions:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{5 \cdot 3 - 2}{3}

5 \cdot 3 - 2 = 13

5 \cdot 3 - 2

Multiply the numbers:

5 \cdot 3 = 15

= 15 - 2

Subtract the numbers:

15 - 2 = 13

= 13

= \frac{13}{3}

= \frac{13}{3}

= (- \frac{3}{5}) \frac{13}{3}

Multiply and divide (left to right)

(- \frac{3}{5}) \frac{13}{3} : - \frac{13}{5}

(- \frac{3}{5}) \frac{13}{3}

Apply rule

(- a) \cdot b = - a \cdot b

(- \frac{3}{5}) \frac{13}{3} = - \frac{3}{5} \cdot \frac{13}{3} = - \frac{13}{5}

= - \frac{13}{5}

= - \frac{13}{5}

((0) - 3)^{2}

- (- 1)^{2} - 5

- (- 1)^{2} - 2

12 + 16 \cdot 2

\frac{3 ( 5 ) ^{2} - 5 ( 5 ) + 1}{( 5 ) - 3}