What is -7/2 (-4)^2+4 ?

The solution to -7/2 (-4)^2+4 is -52

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-7/2 (-4)^2+4

- \frac{7}{2} (- 4)^{2} + 4

- 52

Solution steps

- \frac{7}{2} (- 4)^{2} + 4

Follow the PEMDAS order of operations

Calculate exponents

(- 4)^{2} : 16

(- 4)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 4)^{2} = 4^{2} = 16

= 16

= - \frac{7}{2} \cdot 16 + 4

Multiply and divide (left to right)

- \frac{7}{2} \cdot 16 : - 56

- \frac{7}{2} \cdot 16

Convert element to fraction:

16 = \frac{16}{1}

= - \frac{7}{2} \cdot \frac{16}{1}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

\frac{7}{2} \cdot \frac{16}{1} = \frac{7 \cdot 16}{2 \cdot 1}

= - \frac{7 \cdot 16}{2 \cdot 1}

Cancel

\frac{7 \cdot 16}{2 \cdot 1} : 56

\frac{7 \cdot 16}{2 \cdot 1}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{7 \cdot 16}{2}

Divide the numbers:

\frac{16}{2} = 8

= 7 \cdot 8

Multiply the numbers:

7 \cdot 8 = 56

= 56

= - 56

= - 56 + 4

Add and subtract (left to right)

- 56 + 4 : - 52

- 56 + 4

- 56 + 4 = - 52

= - 52

= - 52

4^{3} \times 4

- 6 + 8 (11 - 4) + 3^{2}

7 \cdot 3 - 2 \cdot 5

3 (- 4)^{2} - 18 (- 4) + 15

[63 + (- 63)] - (65)