What is (-5)^0+(-3)^3-5 ?

The solution to (-5)^0+(-3)^3-5 is -31

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(-5)^0+(-3)^3-5

(- 5)^{0} + (- 3)^{3} - 5

- 31

Solution steps

(- 5)^{0} + (- 3)^{3} - 5

Follow the PEMDAS order of operations

Calculate exponents

(- 5)^{0} : 1

(- 5)^{0}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 5)^{0} = 5^{0} = 1

= 1

= 1 + (- 3)^{3} - 5

Calculate exponents

(- 3)^{3} : - 27

(- 3)^{3}

Apply exponent rule:

(- a)^{n} = - a^{n},

n

is odd

(- 3)^{3} = - 3^{3} = - 27

= - 27

= 1 - 27 - 5

Add and subtract (left to right)

1 - 27 - 5 : - 31

1 - 27 - 5

1 - 27 = - 26

= - 26 - 5

- 26 - 5 = - 31

= - 31

= - 31

10 + 2 \cdot 3

(42 \div 3) \div 7

(8 \times (7 + 8) + 3) \div 3

17 - (5 + 2 \times 3)

\frac{1}{10} (2)^{2}