What is the axis y=x^2+2x-12 ?

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axis y=x^2+2x-12

axis

y = x^{2} + 2 x - 12

x = - 1

Solution steps

y = x^{2} + 2 x - 12

Rewrite

y = x^{2} + 2 x - 12

in the standard form

4 \cdot \frac{1}{4} (y - (- 13)) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - 13), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = x^{2} - 2 x - 4

(y - 1)^{2} = - 6 (x + 2)

y = 3 x^{2} + 12 x - 5

(x - 5)^{2} = 4 (y - 3)

x^{2} + 10 x + 21