What is the axis y=2(x-9)^2 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=2(x-9)^2

axis

y = 2 (x - 9)^{2}

x = 9

Solution steps

y = 2 (x - 9)^{2}

Rewrite

y = 2 (x - 9)^{2}

in the standard form:

4 \cdot \frac{1}{8} (y - 0) = (x - 9)^{2}

Therefore parabola properties are:

(h, k) = (9, 0), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 9

y = s^{2} + s - 2

y^{2} = x

x^{2} = - 125 (y - 20)

y = 3 x^{2} - 6 x + 4

y = 2 (x + 1)^{2} - 2