What is the axis y=s^2+s-2 ?

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axis y=s^2+s-2

axis

y = s^{2} + s - 2

s = - \frac{1}{2}

Solution steps

y = s^{2} + s - 2

Rewrite

y = s^{2} + s - 2

in the standard form

4 \cdot \frac{1}{4} (y - (- \frac{9}{4})) = (s - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{9}{4}, - \frac{1}{2}), p = \frac{1}{4}

Parabola is of the form

4 p (y - h) = (s - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

s = - \frac{1}{2}

y^{2} = x

x^{2} = - 125 (y - 20)

y = 3 x^{2} - 6 x + 4

y = 2 (x + 1)^{2} - 2

y = 3 x^{2} (1.3)