What is the axis 2y=4x-x^2 ?

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axis 2y=4x-x^2

axis

2 y = 4 x - x^{2}

x = 2

Solution steps

2 y = 4 x - x^{2}

Rewrite

2 y = 4 x - x^{2}

in the standard form

4 (- \frac{1}{2}) (y - 2) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 2), p = - \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 2

y = 2 x^{2} - 4 x - 6

y = 6 x^{2} - 37 x - 35

y = (x - 7)^{2}

y = 5 x^{2} + 2 x - 4

y = 2 x^{2} - x - 10