What is the axis y=2x^2-4x-6 ?

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axis y=2x^2-4x-6

axis

y = 2 x^{2} - 4 x - 6

x = 1

Solution steps

y = 2 x^{2} - 4 x - 6

Rewrite

y = 2 x^{2} - 4 x - 6

in the standard form

4 \cdot \frac{1}{8} (y - (- 8)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 8), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = 6 x^{2} - 37 x - 35

y = (x - 7)^{2}

y = 5 x^{2} + 2 x - 4

y = 2 x^{2} - x - 10

y = 3 x^{2} + 2 x + 6