What is the axis x=-((y+3)^2)/(20)+1 ?

The axis x=-((y+3)^2)/(20)+1 is y=-3

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axis x=-((y+3)^2)/(20)+1

axis

y = - 3

Solution steps

x = - \frac{( y + 3 ) ^{2}}{20} + 1

Rewrite

x = - \frac{( y + 3 ) ^{2}}{20} + 1

in the standard form:

4 (- 5) (x - 1) = (y - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (1, - 3), p = - 5

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - 3