What is the axis y=(x+4)^2 ?

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axis y=(x+4)^2

axis

y = (x + 4)^{2}

x = - 4

Solution steps

y = (x + 4)^{2}

Rewrite

y = (x + 4)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, 0), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = 3 x^{2} - 24 x - 15

x^{2} = 28 y

y = - 3 [x^{2} - \frac{16}{3} x + \frac{64}{9} - 4 - \frac{64}{9}]

y^{2} - 4 x + 6 y + 17 = 0

x = (y - 2) (y + 1)