Solution
Solution
Solution steps
Rewrite in the form of a standard hyperbola equation
Therefore Hyperbola properties are:
Popular Examples
4x^2+y^2-8x+4y-8=0(x-1)^2+(y-6)^2=25foci (x^2)/(64)+(y^2)/(36)=1foci vertices x^2+4y^2=16vertices (x-6)^2+(y+5)^2=16
Frequently Asked Questions (FAQ)
What is 2x^2-y^2=4 ?
The solution to 2x^2-y^2=4 is Hyperbola with (h,k)=(0,0),a=sqrt(2),b=2