What is (x-6)^2+(y+5)^2=16 ?

The solution to (x-6)^2+(y+5)^2=16 is Circle with (a,b)=(6,-5),r=4

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(x-6)^2+(y+5)^2=16

(x - 6)^{2} + (y + 5)^{2} = 16

(a, b) = (6, - 5), r = 4

Solution steps

(x - 6)^{2} + (y + 5)^{2} = 16

Rewrite

(x - 6)^{2} + (y + 5)^{2} = 16

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 5))^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (6, - 5), r = 4

4 x^{2} + 4 y^{2} = 25

x^{2} + y^{2} - 12 x - 10 y = - 12

x^{2} + y^{2} - 6 x = 7

4 x^{2} + 4 y^{2} - 16 x + 40 y + 67 = 0

5 x^{2} + 5 y^{2} = 125

What is (x-6)^2+(y+5)^2=16 ?
The solution to (x-6)^2+(y+5)^2=16 is Circle with (a,b)=(6,-5),r=4