What is the axis y= 1/2 x^2+x-1 ?

The axis y= 1/2 x^2+x-1 is x=-1

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axis y= 1/2 x^2+x-1

axis

y = \frac{1}{2} x^{2} + x - 1

x = - 1

Solution steps

y = \frac{1}{2} x^{2} + x - 1

Rewrite

y = \frac{1}{2} x^{2} + x - 1

in the standard form

4 \cdot \frac{1}{2} (y - (- \frac{3}{2})) = (x - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (- 1, - \frac{3}{2}), p = \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 1

y = x^{2} - 15 x

y = \frac{3}{2} (x - 4)^{2} + 3

y = k x^{2} + c

y = + x^{2} - 6

y = - (x + 1)^{2} + 1