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Popular >

center x^2+y^2=16

Solution

center

x^{2} + y^{2} = 16

Solution

(0, 0)

Solution steps

x^{2} + y^{2} = 16

Rewrite

x^{2} + y^{2} = 16

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 4

And the center is:

(0, 0)

Popular Examples

foci 9x^2+4y^2+36x-24y+36=0 foci

9 x^{2} + 4 y^{2} + 36 x - 24 y + 36 = 0

axis y=-(x^2)/(10)+(9x)/(10)+11/5 axis

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

(x^2)/4-(y^2)/4 =1

\frac{x ^{2}}{4} - \frac{y ^{2}}{4} = 1

y^{2} = 6 x

4x^2+y^2+8x-4y+4=0

4 x^{2} + y^{2} + 8 x - 4 y + 4 = 0

Frequently Asked Questions (FAQ)

What is the center x^2+y^2=16 ?
The center x^2+y^2=16 is (0,0)