What is the axis y=-(x^2)/(10)+(9x)/(10)+11/5 ?

The axis y=-(x^2)/(10)+(9x)/(10)+11/5 is x= 9/2

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axis y=-(x^2)/(10)+(9x)/(10)+11/5

axis

x = \frac{9}{2}

Solution steps

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

Rewrite

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

in the standard form

4 (- \frac{5}{2}) (y - \frac{169}{40}) = (x - \frac{9}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{2}, \frac{169}{40}), p = - \frac{5}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{9}{2}

What is the axis y=-(x^2)/(10)+(9x)/(10)+11/5 ?
The axis y=-(x^2)/(10)+(9x)/(10)+11/5 is x= 9/2