What is the axis y=-(x^2)/(10)+(9x)/(10)+11/5 ?

The axis y=-(x^2)/(10)+(9x)/(10)+11/5 is x= 9/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

axis y=-(x^2)/(10)+(9x)/(10)+11/5

axis

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

x = \frac{9}{2}

Solution steps

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

Rewrite

y = - \frac{x ^{2}}{10} + \frac{9 x}{10} + \frac{11}{5}

in the standard form

4 (- \frac{5}{2}) (y - \frac{169}{40}) = (x - \frac{9}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{9}{2}, \frac{169}{40}), p = - \frac{5}{2}

EN : P a r ab o l e S y mm e t ry A x i s T i tl e 2 Eq

x = \frac{9}{2}

What is the axis y=-(x^2)/(10)+(9x)/(10)+11/5 ?
The axis y=-(x^2)/(10)+(9x)/(10)+11/5 is x= 9/2