What is the axis y=(5x+3-x^2)/3 ?

The axis y=(5x+3-x^2)/3 is x= 5/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=(5x+3-x^2)/3

axis

y = \frac{5 x + 3 - x ^{2}}{3}

x = \frac{5}{2}

Solution steps

y = \frac{5 x + 3 - x ^{2}}{3}

Rewrite

y = \frac{5 x + 3 - x ^{2}}{3}

in the standard form

4 (- \frac{3}{4}) (y - \frac{37}{12}) = (x - \frac{5}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{2}, \frac{37}{12}), p = - \frac{3}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{2}

y = 8 x - x^{2} - 17

y = 10 + 5 x - x^{2}

y = x^{2} + 18 x + 81

y = (2 x + 1) (4 - 9 x) - 2 x (3 x + 11)

y = 16 x - 4 x^{2}