What is the axis y=(2x+1)(4-9x)-2x(3x+11) ?

The axis y=(2x+1)(4-9x)-2x(3x+11) is x=-23/48

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axis y=(2x+1)(4-9x)-2x(3x+11)

axis

y = (2 x + 1) (4 - 9 x) - 2 x (3 x + 11)

x = - \frac{23}{48}

Solution steps

y = (2 x + 1) (4 - 9 x) - 2 x (3 x + 11)

Rewrite

y = (2 x + 1) (4 - 9 x) - 2 x (3 x + 11)

in the standard form

4 (- \frac{1}{96}) (y - \frac{913}{96}) = (x - (- \frac{23}{48}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{23}{48}, \frac{913}{96}), p = - \frac{1}{96}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{23}{48}

y = 16 x - 4 x^{2}

y = 4 x^{2} + 6

y = \frac{x ^{2} - 2 x - 19}{5}

y = x^{2} + 8 x - 1

x^{2} + y = 4

What is the axis y=(2x+1)(4-9x)-2x(3x+11) ?
The axis y=(2x+1)(4-9x)-2x(3x+11) is x=-23/48