What is the axis y=-0.5x^2+5.5 ?

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axis y=-0.5x^2+5.5

axis

y = - 0.5 x^{2} + 5.5

x = 0

Solution steps

y = - 0.5 x^{2} + 5.5

Rewrite

y = - 0.5 x^{2} + 5.5

in the standard form:

4 (- 0.5) (y - 5.5) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 5.5), p = - 0.5

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = \frac{1}{2} x^{2} + 9 x + 8

x = (y - 7)^{2} + 1

y = x^{2} + 8

x^{2} + 10 x - 2 y + 21 = 0

y = - 2 (x - 4)^{2} + 5