What is the axis y= 1/2 x^2+9x+8 ?

The axis y= 1/2 x^2+9x+8 is x=-9

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axis y= 1/2 x^2+9x+8

axis

y = \frac{1}{2} x^{2} + 9 x + 8

x = - 9

Solution steps

y = \frac{1}{2} x^{2} + 9 x + 8

Rewrite

y = \frac{1}{2} x^{2} + 9 x + 8

in the standard form

4 \cdot \frac{1}{2} (y - (- \frac{65}{2})) = (x - (- 9))^{2}

Therefore parabola properties are:

(h, k) = (- 9, - \frac{65}{2}), p = \frac{1}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 9

x = (y - 7)^{2} + 1

y = x^{2} + 8

x^{2} + 10 x - 2 y + 21 = 0

y = - 2 (x - 4)^{2} + 5

x = (y + 1) (y + 2)