What is (x^2)/(25)-(y^2)/(16)=1 ?

The solution to (x^2)/(25)-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=5,b=4

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(x^2)/(25)-(y^2)/(16)=1

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 5, b = 4

Solution steps

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{25} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{5 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 5, b = 4

y^{2} + 6 y - 2 x + 13 = 0

x^{2} + y^{2} - 25 = 0

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

\frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

What is (x^2)/(25)-(y^2)/(16)=1 ?
The solution to (x^2)/(25)-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=5,b=4