de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Geometry >

foki y^2+6y-2x+13=0

Lösung

foki

y^{2} + 6 y - 2 x + 13 = 0

Lösung

(\frac{5}{2}, - 3)

Schritte zur Lösung

Rewrite

y^{2} + 6 y - 2 x + 13 = 0

in the standard form

4 \cdot \frac{1}{2} (x - 2) = (y - (- 3))^{2}

(h, k) = (2, - 3), p = \frac{1}{2}

Parabola is symmetric around the x-axis and so the focus lies a distance

p

from the center

(2, - 3)

along the x-axis

(2 + p, - 3)

= (2 + \frac{1}{2}, - 3)

Fasse zusammen

(\frac{5}{2}, - 3)

Graph

Beliebte Beispiele

radius x^2+y^2-25=0

r a d i u s x^{2} + y^{2} - 25 = 0

foki (x^2)/(36)+(y^2)/(16)=1

f oc i \frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

scheitelpunkte (x^2)/4+(y^2)/9 =1

v er t i ces \frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

scheitelpunkte (y^2)/4-(x^2)/5 =1

v er t i ces \frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1

scheitelpunkte 25x^2+9y^2=225

v er t i ces 25 x^{2} + 9 y^{2} = 225