What is the axis y=2x^2-6x+4 ?

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axis y=2x^2-6x+4

axis

y = 2 x^{2} - 6 x + 4

x = \frac{3}{2}

Solution steps

y = 2 x^{2} - 6 x + 4

Rewrite

y = 2 x^{2} - 6 x + 4

in the standard form

4 \cdot \frac{1}{8} (y - (- \frac{1}{2})) = (x - \frac{3}{2})^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{2}, - \frac{1}{2}), p = \frac{1}{8}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{3}{2}

y = (x - 5)^{2} - 1

y = (x + 1) (2 x + 2)

y = (x - 5)^{2} - 4

y = - 3 x^{2} - 2

y = - \frac{1}{11} (x + 5)^{2} + 5