What is the axis (x+4)^2=-6(y-3) ?

The axis (x+4)^2=-6(y-3) is x=-4

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axis (x+4)^2=-6(y-3)

axis

(x + 4)^{2} = - 6 (y - 3)

x = - 4

Solution steps

(x + 4)^{2} = - 6 (y - 3)

Rewrite

(x + 4)^{2} = - 6 (y - 3)

in the standard form:

4 (- \frac{3}{2}) (y - 3) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, 3), p = - \frac{3}{2}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = x^{2} - 4 x + 7

y = 2 x^{2} - 6 x + 4

y = (x - 5)^{2} - 1

y = (x + 1) (2 x + 2)

y = (x - 5)^{2} - 4