What is the axis y=7x^2-5x+9 ?

The axis y=7x^2-5x+9 is x= 5/14

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis y=7x^2-5x+9

axis

y = 7 x^{2} - 5 x + 9

x = \frac{5}{14}

Solution steps

y = 7 x^{2} - 5 x + 9

Rewrite

y = 7 x^{2} - 5 x + 9

in the standard form

4 \cdot \frac{1}{28} (y - \frac{227}{28}) = (x - \frac{5}{14})^{2}

Therefore parabola properties are:

(h, k) = (\frac{5}{14}, \frac{227}{28}), p = \frac{1}{28}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = \frac{5}{14}

y = (x + 2)^{2}

y = - 20 x^{2} + 20000 x - 1800000

(x + 4)^{2} = - 6 (y - 3)

y = x^{2} - 4 x + 7

y = 2 x^{2} - 6 x + 4