What is the axis x-2=(y-1)^2 ?

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axis x-2=(y-1)^2

axis

x - 2 = (y - 1)^{2}

y = 1

Solution steps

x - 2 = (y - 1)^{2}

Rewrite

x - 2 = (y - 1)^{2}

in the standard form:

4 \cdot \frac{1}{4} (x - 2) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (2, 1), p = \frac{1}{4}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 1

y = 6 x^{2} - 29 x - 5

y = 3 x^{2} + x - 6

x^{2} + 4 x - 4 y + 5 = 0

x = 7 y^{2}

y = - 2 x^{2} - 4 x - 7