What is the axis y=9x^2-2 ?

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axis y=9x^2-2

axis

y = 9 x^{2} - 2

x = 0

Solution steps

y = 9 x^{2} - 2

Rewrite

y = 9 x^{2} - 2

in the standard form:

4 \cdot \frac{1}{36} (y - (- 2)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 2), p = \frac{1}{36}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = x^{2} - 7 x + 12

y \geq x^{2}

y = 5 (x + 2)^{2} - 3

y = - \frac{1}{2} x^{2} - 5 x - \frac{15}{2}

x = y - y^{2}