What is the axis y=+x^2-7 ?

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axis y=+x^2-7

axis

y = + x^{2} - 7

x = 0

Solution steps

y = x^{2} - 7

Rewrite

y = x^{2} - 7

in the standard form:

4 \cdot \frac{1}{4} (y - (- 7)) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - 7), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = \frac{1}{4} x^{2} - 3

2 x - y^{2} = 0

y = + 6 x^{2} + 12 x

y^{2} + 6 y + 8 x + 25 = 0

y = 5 x^{2} + 1