What is the axis y=(X-3)^2 ?

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axis y=(X-3)^2

axis

y = (X - 3)^{2}

X = 3

Solution steps

y = (X - 3)^{2}

Rewrite

y = (X - 3)^{2}

in the standard form:

4 \cdot \frac{1}{4} (y - 0) = (X - 3)^{2}

Therefore parabola properties are:

(h, k) = (0, 3), p = \frac{1}{4}

Parabola is of the form

4 p (y - h) = (X - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

X = 3

x^{2} = 6 y

y = - 5 (x + 4)^{2} + 2

x = 3 y^{2} - 30 y + 77

y = (x - 6)^{2} - 9

y^{2} - 12 x + 8 y + 88 = 0