What is x^2+y^2-2x+6y+9=0 ?

The solution to x^2+y^2-2x+6y+9=0 is Circle with (a,b)=(1,-3),r=1

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x^2+y^2-2x+6y+9=0

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

(a, b) = (1, - 3), r = 1

Solution steps

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

Rewrite

x^{2} + y^{2} - 2 x + 6 y + 9 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 3))^{2} = 1^{2}

Therefore the circle properties are:

(a, b) = (1, - 3), r = 1

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{25} = 1

\frac{x ^{2}}{9} + \frac{y ^{2}}{5} = 1

y^{2} = 5 x

9 x^{2} - 4 y^{2} = 36

\frac{x ^{2}}{9} - \frac{y ^{2}}{4} = 1

What is x^2+y^2-2x+6y+9=0 ?
The solution to x^2+y^2-2x+6y+9=0 is Circle with (a,b)=(1,-3),r=1