What is the axis y=2250(0.015-0.001x)^2+6000x ?

The axis y=2250(0.015-0.001x)^2+6000x is x=-(5999.9325)/(0.0045)

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axis y=2250(0.015-0.001x)^2+6000x

axis

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

x = - \frac{5999.9325}{0.0045}

Solution steps

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

Rewrite

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

in the standard form

4 \cdot 111.11111 \dots (y - 0) = (x - (- \frac{5999.9325}{0.0045}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5999.9325}{0.0045}, 0), p = 111.11111 \dots

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{5999.9325}{0.0045}

y - 2 = 3 (x - 5)^{2}

y = 160 x - 16 x^{2}

x^{2} + 6 x + 3 y + 2 = 0

y = - 2 x^{2} - 3 x + 5

y = - 0.1 x^{2} + 0.8 x + 98.8

What is the axis y=2250(0.015-0.001x)^2+6000x ?
The axis y=2250(0.015-0.001x)^2+6000x is x=-(5999.9325)/(0.0045)