What is the axis y=2250(0.015-0.001x)^2+6000x ?

The axis y=2250(0.015-0.001x)^2+6000x is x=-(5999.9325)/(0.0045)

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axis y=2250(0.015-0.001x)^2+6000x

axis

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

x = - \frac{5999.9325}{0.0045}

Solution steps

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

Rewrite

y = 2250 (0.015 - 0.001 x)^{2} + 6000 x

in the standard form

4 \cdot 111.11111 \dots (y - 0) = (x - (- \frac{5999.9325}{0.0045}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5999.9325}{0.0045}, 0), p = 111.11111 \dots

EN : P a r ab o l e S y mm e t ry A x i s T i tl e 2 Eq

x = - \frac{5999.9325}{0.0045}

What is the axis y=2250(0.015-0.001x)^2+6000x ?
The axis y=2250(0.015-0.001x)^2+6000x is x=-(5999.9325)/(0.0045)