What is the axis y=x^2-2x-15 ?

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axis y=x^2-2x-15

axis

y = x^{2} - 2 x - 15

x = 1

Solution steps

y = x^{2} - 2 x - 15

Rewrite

y = x^{2} - 2 x - 15

in the standard form

4 \cdot \frac{1}{4} (y - (- 16)) = (x - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, - 16), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 1

y = x - \frac{1}{2} x^{2}

3 y^{2} + 4 x - 24 y + 44 = 0

y = (x + 1)^{2} + 1

y = 3 x^{2} - 5 x + 1

y = (x - 3)^{2}