What is the axis 3y^2+4x-24y+44=0 ?

The axis 3y^2+4x-24y+44=0 is y=4

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axis 3y^2+4x-24y+44=0

axis

3 y^{2} + 4 x - 24 y + 44 = 0

y = 4

Solution steps

3 y^{2} + 4 x - 24 y + 44 = 0

Rewrite

3 y^{2} + 4 x - 24 y + 44 = 0

in the standard form

4 (- \frac{1}{3}) (x - 1) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (1, 4), p = - \frac{1}{3}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = 4

y = (x + 1)^{2} + 1

y = 3 x^{2} - 5 x + 1

y = (x - 3)^{2}

y = 84 x - x^{2}

(y + 6)^{2} = 12 (x + 1)