What is the axis x^2+12y=0 ?

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

axis x^2+12y=0

axis

x^{2} + 12 y = 0

x = 0

Solution steps

x^{2} + 12 y = 0

Rewrite

x^{2} + 12 y = 0

in the standard form:

4 (- 3) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 3

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = 0

y = 2 x - x^{2}

y = - x^{2} + 4 x - 4

y = x^{2} - 1

y = x^{2} - 12 x + 35

(x + 1)^{2} = (y + 4)