What is the axis y=0.00225x^2+5999.9325x+0.50625 ?

The axis y=0.00225x^2+5999.9325x+0.50625 is x=-(5999.9325)/(0.0045)

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axis y=0.00225x^2+5999.9325x+0.50625

axis

x = - \frac{5999.9325}{0.0045}

Solution steps

y = 0.00225 x^{2} + 5999.9325 x + 0.50625

Rewrite

y = 0.00225 x^{2} + 5999.9325 x + 0.50625

in the standard form

4 \cdot 111.11111 \dots (y - 0) = (x - (- \frac{5999.9325}{0.0045}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{5999.9325}{0.0045}, 0), p = 111.11111 \dots

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - \frac{5999.9325}{0.0045}

What is the axis y=0.00225x^2+5999.9325x+0.50625 ?
The axis y=0.00225x^2+5999.9325x+0.50625 is x=-(5999.9325)/(0.0045)