What is the foci 4x^2-9y^2=36 ?

The foci 4x^2-9y^2=36 is (sqrt(13),0),(-sqrt(13),0)

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foci 4x^2-9y^2=36

foci

4 x^{2} - 9 y^{2} = 36

(13, 0), (- 13, 0)

Solution steps

(h + c, k), (h - c, k)

Calculate Hyperbola properties

4 x^{2} - 9 y^{2} = 36 :

Right-left Hyperbola with

(h, k) = (0, 0), a = 3, b = 2

(0 + c, 0), (0 - c, 0)

Compute

c :

c = 3^{2} + 2^{2} : 13

(0 + 13, 0), (0 - 13, 0)

Refine

(13, 0), (- 13, 0)

y \leq - 3 x^{2} + 1

f (x) = x^{2} + 2 x - 3

- (x + 3)^{2} - 1

49 x^{2} + 16 y^{2} = 784

3 x^{2}

What is the foci 4x^2-9y^2=36 ?
The foci 4x^2-9y^2=36 is (sqrt(13),0),(-sqrt(13),0)