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Popular >

y^2+x+y=0

Solution

y^{2} + x + y = 0

Solution

(h, k) = (\frac{1}{4}, - \frac{1}{2}), p = - \frac{1}{4}

Solution steps

y^{2} + x + y = 0

Rewrite

y^{2} + x + y = 0

in the standard form

4 (- \frac{1}{4}) (x - \frac{1}{4}) = (y - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{1}{4}, - \frac{1}{2}), p = - \frac{1}{4}

Popular Examples

foci x^2=28y foci

x^{2} = 28 y

axis y=2-x-2x^2 axis

y = 2 - x - 2 x^{2}

foci (x^2)/8+(y^2)/3 =1 foci

\frac{x ^{2}}{8} + \frac{y ^{2}}{3} = 1

vertices f(x)=x^2+6x+5 vertices

f (x) = x^{2} + 6 x + 5

4x^2-12y^2-16x-72y-44=0

4 x^{2} - 12 y^{2} - 16 x - 72 y - 44 = 0

Frequently Asked Questions (FAQ)

What is y^2+x+y=0 ?
The solution to y^2+x+y=0 is Parabola with (h,k)=(1/4 ,-1/2),p=-1/4